Take any two numbers: say, and 3, Halve the first number again and again, discarding any fractional remainder, until you reach the number 1. Thus: , 58, 29, 14, 7, 3, 1. Double the second as many times as you halved the first.
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Take any two numbers: say, and 3, Halve the first number again and again, discarding any fractional remainder, until you reach the number 1. Thus: , 58, 29, 14, 7, 3, 1. Double the second as many times as you halved the first. Thus: 3,; 6,; 12,; 24,; 48, ; 96,; , Write these series alongside each other, and cross out every even number in the halves column and its partner in the doubles column.
Thus, as shown in the following columns, the even numbers in the halves column , 58, and 14 are crossed out along with their companions in the doubles column 3,; 6,; and 24, , regardless of whether these are even or odd. Add the numbers that remain in the doubles column only. The resulting sum will be equal to the product of the two numbers you started with. He showed that it can be explained by using base two!
I will give a short summary of his idea and then attach his letter below. Thanks again to Shekhar for providing the explanation! I am 15 years old. My English may be a little poor. In this sequence I have reached the trick of multiplying two numbers. It said that we have to half one number till it reaches 1, and double the second number.
After canceling the even number s in the first part and the corresponding numbers in the second part, the sum of the leftover numbers in the second part will be the product of the two numbers. Here I am trying to give an explanation.
I have not taken any help from anyone to find this explanation. I would like to get a reply of this mail as soon as possible. It is like subtracting 1 and dividing by 2. The second number is multiplied with this multiples of 2 and then the products are added. Waiting for reply. Send any comments or questions to: David Pleacher.
Figuring: The Joy of Numbers
Devi, Shakuntala. This book shows the reader how to perform mathematical operations in a more efficient and faster way without the aid of a calculator. This is the only one book I have read about this remarkable prodigy, and thought it was worth writing about. Shakuntala Devi Shakuntala Devi was a prodigy who frequently demonstrated on television and lecture halls all over the world that she could perform numerical arithmetic in her head. If you wanted to know the cube root of , or the day of the week on 8th December , or the eleventh power of your telephone number, she could give the answers within seconds. This ability won her a place in the Guinness Book of Records where she calculated the twenty-third root of a digit number. Unfortunately, she cannot teach us all how to perform such feats, but she shows some of the methods she used through this book.